Rakutenpoar

In this video I am going to show you that how you can proof a3b3c3=3abc when abc=0It is a special identity of polynomial of class 9thIt often comes inExample Solve 8a 3 27b 3 125c 3 – 90abc Solution This proceeds as Given polynomial (8a 3 27b 3 125c 3 – 90abc) can be written as (2a) 3 (3b) 3 (5c) 3 – 3(2a)(3b)(5c) And this represents identity a 3 b 3 c 3 3abc = (a b c)(a 2 b 2 c 2 ab bc ca) Where a = 2a, b = 3b and c = 5c Now apply values of a, b and c on the LHS of identity ie a 3 b 3 c 3Since B is an empty set, the statement x∈B is false for all x, so (∀x)( x∈Β ⇒ x∈Α ) is also true Thus, B ⊆ Α Since A ⊆ B and B ⊆ Α we have A = B We will use a direct proof here but later we will use another technique to prove this How Do I Prove 1 A V B C 2 A V C G O G V O Philosophy Stack Exchange (a+b+c)^3 formula proof